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Mathematics 9 Online
OpenStudy (anonymous):

Velocity question

OpenStudy (anonymous):

OpenStudy (aum):

Find the derivative: velocity = dx/dt

OpenStudy (johnweldon1993):

Well that equation you are given looks to be the position equation To get velocity, we need to take the derivative of this equation

OpenStudy (johnweldon1993):

Then then take the derivative of the newly derived velocity equation to find the acceleration.

OpenStudy (anonymous):

@johnweldon1993 so i took the derivative and got 2.92-2t

OpenStudy (anonymous):

then plug in 3.10 for t but thats not the right answer

OpenStudy (johnweldon1993):

You tried putting in -3.28 for an answer and it was incorrect?

OpenStudy (anonymous):

oh thats right... i swear i put that in already..haha

OpenStudy (anonymous):

so the acceleration is jsut the derivative of the velocity?

OpenStudy (johnweldon1993):

Lol perhaps forgot the negative sign? Regardless, yes now just take the derivative of the velocity to find the acceleration

OpenStudy (anonymous):

so 2?

OpenStudy (johnweldon1993):

Not quite...

OpenStudy (anonymous):

oh forgot the - again

OpenStudy (anonymous):

thanks for your help

OpenStudy (johnweldon1993):

Anytime!

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