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OpenStudy (anonymous):
Velocity question
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OpenStudy (anonymous):
OpenStudy (aum):
Find the derivative: velocity = dx/dt
OpenStudy (johnweldon1993):
Well that equation you are given looks to be the position equation
To get velocity, we need to take the derivative of this equation
OpenStudy (johnweldon1993):
Then then take the derivative of the newly derived velocity equation to find the acceleration.
OpenStudy (anonymous):
@johnweldon1993 so i took the derivative and got 2.92-2t
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OpenStudy (anonymous):
then plug in 3.10 for t but thats not the right answer
OpenStudy (johnweldon1993):
You tried putting in -3.28 for an answer and it was incorrect?
OpenStudy (anonymous):
oh thats right... i swear i put that in already..haha
OpenStudy (anonymous):
so the acceleration is jsut the derivative of the velocity?
OpenStudy (johnweldon1993):
Lol perhaps forgot the negative sign? Regardless, yes now just take the derivative of the velocity to find the acceleration
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OpenStudy (anonymous):
so 2?
OpenStudy (johnweldon1993):
Not quite...
OpenStudy (anonymous):
oh forgot the - again
OpenStudy (anonymous):
thanks for your help
OpenStudy (johnweldon1993):
Anytime!
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