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100 g of water is heated from 30 degree C to 50 degree C the change in its internal energy a 8.4 k J b 84 k J c 2.1 k J d 4.2k J
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@Opcode @kropot72 @Hero @inkyvoyd @Kainui @Luigi0210
\[Q = mc \Delta T\]
@Schrodingers_Cat could you explain the formula?
The change in heat will equal the change in internal energy.
mc is equal to 100 kg ??
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100 x 10^-3 kg * ?
c is the specific heat of water.
M is mass and DeltaT is the change in temperature.
Q = 100 X 417 x 20 Am I put the right values ???
@Schrodingers_Cat can you please show me your solution ?
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Q = 100(4.179)(50 -30) = 8352 J
so in kJ it will be 8.35 right ?
Yep :)
Oh thank you so much ^_^ @Schrodingers_Cat
can you help me with few more ?
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