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Physics 26 Online
OpenStudy (anonymous):

100 g of water is heated from 30 degree C to 50 degree C the change in its internal energy a 8.4 k J b 84 k J c 2.1 k J d 4.2k J

OpenStudy (anonymous):

@Opcode @kropot72 @Hero @inkyvoyd @Kainui @Luigi0210

OpenStudy (schrodingers_cat):

\[Q = mc \Delta T\]

OpenStudy (shadowlegendx):

@Schrodingers_Cat could you explain the formula?

OpenStudy (schrodingers_cat):

The change in heat will equal the change in internal energy.

OpenStudy (anonymous):

mc is equal to 100 kg ??

OpenStudy (anonymous):

100 x 10^-3 kg * ?

OpenStudy (schrodingers_cat):

c is the specific heat of water.

OpenStudy (schrodingers_cat):

M is mass and DeltaT is the change in temperature.

OpenStudy (anonymous):

Q = 100 X 417 x 20 Am I put the right values ???

OpenStudy (anonymous):

@Schrodingers_Cat can you please show me your solution ?

OpenStudy (schrodingers_cat):

Q = 100(4.179)(50 -30) = 8352 J

OpenStudy (anonymous):

so in kJ it will be 8.35 right ?

OpenStudy (schrodingers_cat):

Yep :)

OpenStudy (anonymous):

Oh thank you so much ^_^ @Schrodingers_Cat

OpenStudy (anonymous):

can you help me with few more ?

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