Question

the voltage between the anode and the cathode of an electron gun is 2500V. show that the electrons are emitted from the gun at about 3x10^7 m/s, any ideas?

Answer 1

E = W = QV (volt) = 0.5Mv^2

Answer 2

@goive123 ??

Answer 3

it is using electrong charge and the masss of electrons; i have been given the values

Answer 4

Thus V = 0.5 M v^2 / Q .