Question

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Answer 1

lol you trolling? :/

Answer 2

integrate 2e^{10x}.dx

Answer 3

\[\Large \int 2e^{10x}dx\]

Answer 4

yes...how to solve it ?

Answer 5

If it were \(\large e^x\) instead, could you integrate it? :)

Answer 6

2\(e^x\) ?

Answer 7

Something like that. The derivative of \(\large e^x\) is itself, after all.

Answer 8

ok

Answer 9

So, I suggest you make a substitution. To try to turn that 10x exponent into a single variable.

Let u = 10x
Can you work out the rest/

Answer 10

are you indicating towards chain rule ?

Answer 11

Yup. Only for integration, though.

Are you new to this stuff?

Answer 12

yes....m not a math guy....

Answer 13

can u elaborate the step a lill more ?

Answer 14

Let me try another approach. This much is clear, yes?
\[\Large \int e^x dx = e^x + C\]

Answer 15

yes

Answer 16

Okay... This is also clear?
\[\Large \int ke^x dx = ke^x + C\]

Answer 17

yes