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Mathematics 18 Online
OpenStudy (anonymous):

Simplify completely: the quantity 14 times x to the 5th power times y to the 4th power plus 21 times x to the third power times y to the 2nd power all over 7 times x to the third power times y

OpenStudy (anonymous):

@midhun.madhu1987

OpenStudy (midhun.madhu1987):

can u draw it?

OpenStudy (anonymous):

\[\frac{14 x^5 y^4+21 x^3 y^2}{7 x^3 y}=2 x^2 y^3+3 y \]

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