A roller coaster moves 200 ft. horizontally, hen rises 135 ft at an angle 30degrees above the horizontal. It then travels 135 ft at an angle of 40 degrees below horizontal. What is its displacement from its starting point at the end of this movement? Use graphical techniques and also find the magnitude and direction.

Question

kkutie7 · Answer

Answer: 537.26 ft horizontal and 48.22 ft vertical, 539.41 ft at 5.13◦ how do I get here?

anonymous · Answer

Draw a picture: http://i279.photobucket.com/albums/kk154... x_tot = 200 + [135cos(30°)] + [135cos(-40°)] x_tot = 420.3294293 ft y_tot = [135sin(30°)] + [135sin(-40°)] y_tot = -19.27632731 ft Displacement = √(x² + y²) Displacement = √[(420.3294293)² + (-19.27632731)²] Displacement = 420.771204 ft Displacement = 421 ft tanθ = (y / x) tanθ = (-19.27632731 / 420.3294293) θ = arctan (-0.0458600468) θ = -2.625747386° θ = -2.63° Displacement = 421 ft at 2.63° below the horizontal.

anonymous · Answer

Displacement = 421 ft at 2.63° below the horizontal.

anonymous · Answer

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kkutie7 · Answer

Link is broken =(

anonymous · Answer

:( sorry

kkutie7 · Answer

Does it look something like this?
|dw:1409272394874:dw|