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how to you factor 2x^2+5x-7?
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that's alot of primes. what ideas do you have?
2x(x + 2.5) -7
i have no idea
ok, so, first thing is we want to get rid of that nasty 2
ok
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so let's divide it out
can you do that?
\[=x(2x+7) - (2x+7)\] =(x-1)(2x+7)
how did you get that?
i was just going to complete the square
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but popitree's is nicer
the form is ax^2+bx+c; so we need some combination so that we can take common out here a.c = 2*-7; = -14; now as the sign is negative we need two numbers when subtracted will result in b that is 5 here 7-2=5 so basically it is 2x^2+x(7-2)-7 then take the commons
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