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2^(x-4)+10=22
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If we subtract 10 from both sides, the result is: \[\large 2^{(x-4)}=12\ ......(1)\] The first step in solving (1) is to take logs of both sides, remembering that: \[\large \log_{} a ^{x}=x \log_{} a\]
@meg_72 Can you do this first step?
would it be x=7.5?
@meg_72 Is that an answer choice for the question?
i dont have answer choices for this one
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Well how did you arrive at x = 7.5 ?
\[\large (x-4)\log2=\log12\ ......(2)\] \[\large x-4=\frac{\log12}{\log2}=3.585\ .......(3)\] Can you find the value of x from equation (3)?
@Probhat Try testing your proposed solution in the original equation. Note: You are incorrect in your first step.
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