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Mathematics 16 Online
OpenStudy (anonymous):

Find the equation of the sphere if one of its diameters has endpoints (-7, -4, -8) and (-4, 2, 1).

OpenStudy (anonymous):

OpenStudy (anonymous):

this is what i've done. i found the distance, divided by 2 to get radius. then i found the center by saying the point halfway between the x, y, and z points. plugged my equation in and webwork says it's wrong. did i mess up somewhere in my algebra or what?

OpenStudy (across):

Find the center of the sphere by using the 3D midpoint formula\[\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2},\frac{z_1+z_2}{2}\right).\]

OpenStudy (across):

Sorry, I didn't see you posted your work. I'll review it.

OpenStudy (anonymous):

yeah, i did that. just got the math wrong on the last one, but the answer is still wrong somewhere

OpenStudy (across):

The \(z\) coordinate of your center is \(-5\). Why?

OpenStudy (anonymous):

cause i goofed. i tried inputing this instead. (x+5.5)^2+(y+1)^2+(z+3.5)^2-(sqrt(145)/2)^2 still wrong.

OpenStudy (across):

That is strange. I got: \((x+5.5)^2+(y+1)^2+(z+3.5)^2=145/4\).

OpenStudy (anonymous):

weird. ok. i'll have to send this to my teacher then and ask wtf....thanks across.

OpenStudy (across):

Wait a moment.

OpenStudy (anonymous):

ok

OpenStudy (across):

I took your measurement of distance to arrive at my conclusion, but just realized you said that \(9^2=100\).

OpenStudy (anonymous):

oops....i did that the other day too. said 3+3=9....grr.....thanks!

OpenStudy (across):

You are welcome. Let me know if the answer passes.

OpenStudy (anonymous):

webwork says :"The answer above is correct."................thanks!

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