Any help on this...? deals with irrational and rational numbers.
would it be the first one because the square roots cancel each other leaving the seven as the final answer
Yep that's correct @meln_n !
yeah! thanks mine helping me on the other one... this one was easy but the other i have to add three set of numbers that include as well square roots @math&ing001
Ok sure
Can you add each one of them and show me what you get ?
ok n_n
oh wait !! i got three for the third one .... \[(2-\sqrt{2})+(1-\sqrt{2}) = 3-2\sqrt{2} +2\sqrt{2} = 3\]
does that mean this one would be the answer because its a rational number ??? @math&ing001
Yep ^^
yay! thank you i get this then i dont which makes me feel everything is wrong lol @math&ing001
Happens, welcome !
im sorry to bother again but this one is sort of funky .... i added all of the problems but there seems to be three irrational answers instead of one ??? how do i eliminate the rest to get an answer??? am i missing something ... @math&ing001
It's because it's not addition they're telling you to do but product.
oppssss! omgoshhh what a fail -_- ... mmmhhh even after i multiply my answers are still all rational numbers -23,10,2,3,23 .... @math&ing001
@math&ing001
You made a mistake on #4 sqrt(2) (5-sqrt(2)) = 5sqrt(2) - 2
ohhhhhhh ok kinda didnt see what your doing but GOT IT soo the answer would be |dw:1409328435723:dw| @math&ing001
okkkkk thank youuu
oh wait or does it stay at 5 (square root 2) - 2
Yep !
For this problem.... i dont really understand how to multiply the third and fourth ... like for the fourth would the answer be 18 ?? @math&ing001
Yep it's 18 for the fourth and 9sqrt(2) ( sqrt(2) + 9) = 18 + 81 sqrt(2)
ok thanks n_n @math&ing001
Welcome !
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