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tan(3x)(tanx-1)=0 [0,2pi)
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I get 0, pi/4, pi/6, 5pi/4, are there other solutions?
pi/3,
4pi/3
7pi/4
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why? then it would be -1
3pi/4
tan (3x) (tanx-1) =0 either tan(3x) =0 or tanx -1 =0, right?
now, tan (3x) =0 iff sin (3x) =0 , ok?
tanx-1=0
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sin ( 3x) =0 when 3x =0 or 3x =pi --> x = pi/2
* x =pi/3
I get the 3x, but if tanx-1 = 0 then tanx =1 right?
yes,
so that happens at 45 degrees or 225 degrees
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nevermind...I see it now
not just that, \( tan = \dfrac {sin}{cos}=1 \rightarrow, sin =cos\)
Thanks
ok
I love helping students who knows what he is doing and willing to fight back if I am wrong.
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