Question

help with one question of calculus (:

Answer 1

To three decimal places, find the value of the first positive x-intercept for the function f(x) = 2cos(x + 4).

Answer 2

@KeithAfasCalcLover

Answer 3

i got –2.712

Answer 4

negative 2.712

Answer 5

The first "POSITIVE"?

Answer 6

oh shoot, ok one sec let me redo it

Answer 7

ok i got 1.712 (:

Answer 8

No good. Are you working with the right function? How did you get that?

Answer 9

Well hi again Mondona :) the solution to the equation is:
\[x=\pi\left(2n-\frac{1}{2}\right)-4, n\in Z\]

Answer 10

When you solve the equation \(2cos(x+4)=0\)

Answer 11

0.712, i have no idea why i added a 1 in there

Answer 12

That's better.

Answer 13

Right!

Answer 14

Coresponding to n=1