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Solve y'=(y^3+2xy^2+x^2*y+x^3)/(x(y+x)^2) implicitly.
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I got (u+1)^2 du=dx/x integrate, (u+1)^3/3=ln abs(x)+C (u+1)^3=3ln abs(x)+C u+1=(3*ln abs(x)+C)^1/3 u=(3*ln abs(x)+C)^(1/3)-1 y/x=(3*ln abs(x)+C)^(1/3)-1 But the answer in the book is (y+x)^3=3x^3(ln abs(x)+C). How do I get to the answer from there?
@myininaya
this looks same as previous problem ?
Yes, but how do I get to the answer from there? The answer I got is different from the answer in the book. It's a bit strange.
(u+1)^3=3ln abs(x)+C substitute u = y/x
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so I substitute that now? I substituted after I solved for u.
you don't need to solve u or x or y explicitly unless you're asked explicitly to solve in the question
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