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Mathematics 16 Online
OpenStudy (mokeira):

someone please explain this to me.

OpenStudy (mokeira):

For the given function f(x), write a formula for \[\frac{ f(x+h)-f(x) }{ h }\]and if possible simplify \[f(x)=x^2-2x+3\]

OpenStudy (anonymous):

f(x+h)=(x+h)^2-2(x+h)+3 f(x+h)=x2+h2+2xh-2x-2h+3 so f(x+h)-f(x)=x2+h2+2xh-2x-2h+3-x2+2x-3 f(x+h)-f(x)=h2+2xh-2h f(x+h)-f(x)=h(h+2x-2) f(x+h)-f(x)/h=h(h+2x-2)/h f(x+h)-f(x)/h=h+2x-2

OpenStudy (anonymous):

now if h->0 then f(x)=2x-2 which shows that it is exactly the derivative of above function.. and also the above given formua is gen.def.of derivative of any functio.n.

OpenStudy (mokeira):

wow...great. thanks!

OpenStudy (anonymous):

yw @Mokeira

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