Question

What is the equation of the ellipse with foci (0, 4), (0, -4) and vertices (0, 8), (0, -8)?
A. x squared divided by 16 minus y squared divided by 64 equals 1
B. x squared divided by 16 plus y squared divided by 64 equals 1
C. x squared divided by 48 plus y squared divided by 64 equals 1
D. x squared divided by 48 minus y squared divided by 64 equals 1

Ive narrowed it to B and C

Answer 1

(x-h)^2/b^2+(y-k)^2/a^2=1, a>b, (h,k) being the (x,y) coordinates of the center.

Answer 2

For given ellipse:
center: (0,0)
c=4 (from foci)

Answer 3

I got B is that right? LOL

Answer 4

its C

Answer 5

.-.
ok... for sure?

Answer 6

it wud be x2/48+y2 /64

Answer 7

Oh Oh ok i get it
wha tbaout this one? What is the equation of the ellipse with co-vertices (-20, 0), (20, 0) and foci (0, -8), (0, 8)?

Answer 8

(x^2/400) +(y^2+464)=1?

Answer 9

b2=400
c2=64
a2=b2+c2=400+64
x2/464 + y2/400=1