Question

Solve the system by graphing.
y = 4/3x + 3
x2 + (y ̶ 3)2 = 25
A. (-3, 7) and (-1, 3)
B. (-3, 7) and (3, -1)
C. (7, -3) and (-1, 3)
D. (7, -3) and (3, -1)

I get (3,7) and (-3, -1)

Answer 1

Here are your points of intersection:



One way to check your answer is to see if when x=3 that y =7 for BOTH equations:

checking 1st equation
$$
y=\cfrac{4}{3}(3)+3=7\\
$$
checking 2nd equation
$$
3^2+(7-3)^2=9+16=25
$$
This checks out for both. Take the next point x=-3 and see if y=-1
$$
y=\cfrac{4}{3}(-1)+3=-1\\
$$
checking 2nd equation
$$
3^2+(-1-3)^2=9+16=25
$$
So both equations match.

Your answer is therefore correct.