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Mathematics 16 Online
OpenStudy (anonymous):

For the graph below, what should the domain be so that the function is at least 300? graph of y equals minus 2 times the square of x plus 50 times x plus 300 x greater than or equal to 0 -5 is less than or equal to x which is less than or equal to 30 0 is less than or equal to x which is less than or equal to 25. all real numbers

OpenStudy (anonymous):

Please helpppp

OpenStudy (anonymous):

What math is this ?

OpenStudy (anonymous):

Algebra I Quadratic Functions and Graphs.

OpenStudy (anonymous):

Hmmmmmmm . Yea I suck at math lmao .

OpenStudy (anonymous):

Do you have answer choices to choose from ?

OpenStudy (anonymous):

Yeah. They are there. They just dont say a, b, c, d, etc. Lol

OpenStudy (anonymous):

x greater than or equal to 0 -5 is less than or equal to x which is less than or equal to 30 0 is less than or equal to x which is less than or equal to 25. all real numbers

OpenStudy (anonymous):

ohhh i see . One sec I'll try to figure it out . I'll let you know .

OpenStudy (anonymous):

I'm not making any promises though

OpenStudy (anonymous):

Okay thanks. :)

OpenStudy (anonymous):

It's B. Lol Just figured it out

OpenStudy (anonymous):

Bret threw a baseball up in the air. The following table represents the height f(t), in meters, of the ball above the ground at time t seconds: Time (t) (in seconds) Height f(t) (in meters) 0 3 2 4 4 3 6 0 Which of the following is represented by the y-intercept of f(t)? The ball touches the ground after 6 seconds. The ball was thrown from a height of 3 meters. The ball reaches a maximum height of 4 meters. The ball reaches the maximum height in 2 seconds.

OpenStudy (anonymous):

Yea I have no idea . I REALLY suck at math lmao

OpenStudy (anonymous):

The ball was thrown from a height of 3 meters

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

np

OpenStudy (anonymous):

The steps to derive the quadratic formula are shown below: Step 1 ax^2 + bx + c = 0 Step 2 ax^2 + bx = - c Step 3 x^2 + b over a times x equals negative c over a Step 4 x^2 + b over a times x plus b squared over 4 times a squared equals negative c over a plus b squared over 4 times a squared Step 5 x^2 + b over a times x plus b squared over 4 times a squared equals negative 4 multiplied by a multiplied by c, all over 4 multiplied by a squared plus b squared over 4 times a squared Step 6 the square of the quantity x plus b over 2 times a equals b squared minus 4 multiplied by a multiplied by c, all over 4 times a squared Step 7 x plus b over 2 times a equals plus or minus square root of the quantity b squared minus 4 times a times c over 4 times a squared equals plus or minus square root of b squared minus 4 times a times c, all divided by 4 times a Step 8 x = -negative b over 2 times a plus or minus square root of b squared minus 4 times a times c, all divided by 2 times a Step 9 x = negative b plus or minus square root of b squared minus 4 times a times c, all divided by 2 times a Which of the following is the first incorrect step? Step 4 Step 6 Step 7 Step 8

OpenStudy (anonymous):

step 4 and step 6 are correct so it leaves step 7&8 which i'm not sure about.. sorry

OpenStudy (anonymous):

No that helps a lot. Thanks

OpenStudy (anonymous):

If d = p + 0.5at2, which equation is solved for t? t = square root of d minus p minus 0.5 over a t = square root of d plus p minus 0.5 over a t = square root of d plus p over 0.5 times a t = square root of d minus p over 0.5 times a

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