Integral problem
integral of \[e ^{x}\cos ^{2}x\]
I know I have to do it with integration by parts and I do it like that but I get the wrong answer, here's a picture so maybe someone can see my mistake.
The correct answer is \[\frac{ 2e ^{x}\sin2x + e ^{x}\cos2x}{ 5 }\]
So I'm not that far off, I just don't see what I do wrong
couldn't get how you got that 4I anyways, how about trying to represent cos^2 x in term of cos 2x ?? then using the standard integral of e^(ax) cos (bx)
First the "correct" answer I thought it was wasn't correct. And you were right about doing it with terms of cos2x first. I got the right answer. I still have no idea what I did wrong with the other way but nevermind.
do you need a constant of integration
im still not sure how to get the sign right
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