Question

@BSwan @rational @UnkleRhaukus

Answer 1

\[\frac{ 3 }{ a-6 }-\frac{ 1 }{ a-2}=3\]

Answer 2

what you tried so far ?

Answer 3

nothing I just posted it

Answer 4

\[-> 3a - 6 - a - 6/ a^2 - 2a -6a -12 = 3\]
now do you get the idea

Answer 5

2a - 12/ a^2 -8a - 12 = 3
..now can you do it on yar own?

Answer 6

is that the work im supposed to copy to get the answer?

Answer 7

nah you are supposed to evaluate and answer it yourself..try it's easy

Answer 8

im supposed to show work though

Answer 9

\[2a - 12 = 3a^2 -24a - 36 => 26a -3a^2 = -36 -12=> 26a-3a^2 = -48\]

now do you get the process now

Answer 10

is that the answer

Answer 11

wait...
\[2a - 6 - a + 6 /a^2 -2a -6a + 12 = 3\]
\[\frac{ a }{ a^2 - 8a + 12 } = 3 => a = 3a^2 -24a + 36 => 25a-3a^2 = 36 => \]

....are you sure that the EQN. is right nd there's no error like you previous exp. function question>>>confused.....

Answer 12

no there is no mistake just plleeease tell me the answer

Answer 13

\(\Huge \frac{ 3 }{ a-6 }-\frac{ 1 }{ a-2}=3 \)

\(\large \frac{ 3(a-2) }{( a-6)(a-2) }-\frac{ (a-6) }{ (a-2)(a-6)}=\frac{3(a-2) (a-6) }{ (a-2)(a-6)} \)

thus
\(\large 3(a-2)-(a-6)=3(a-2)(a-6)\)
\(\large 3a-6-a+6=3(a^2-8a+12)\)

\(\Huge -3a^2+26a-36=0\)
quadratic equation , solve for a

Answer 14

uh..got it a has two solutions:
\[a = 1/3 \times (13-\sqrt{6}))\]
and
\[a = \frac{ 1 }{ 3 }(13+\sqrt{61})\]