Question

Graph the hyperbola with equation ((x+1)^2/9)-((y+4)^2/25) = 1

Answer 1

@nincompoop

Answer 2

What is the center of this hyperbola?
What are the 'a' and 'b' values?

Compare it to \(\Large \frac{(x−h)^2}{a^2}−\frac{(y−k)^2}{b^2}=1 \)
where (h,k) is the center.

Answer 3

a=3 b=5 and then (-1,-4)?

Answer 4

Yes. Plot the point (-1, -4). That will be the center of the hyperbola.
Draw a horizontal line from the center and on it mark 'a' units to the right and 'a' units to the left. Those will be the vertex. Then draw the hyperbola.

Answer 5

thats a reaaallly bad drawing but kind of like that?