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An equilateral triangle is inscribed in a circle of radius r. See the figure. Express the circumference C of the circle as a function of the length x of a side of the triangle. [Hint: First show that r^2 = x^2/3.]
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|dw:1409521151813:dw|
x is = to (square root of 3) * r
If you found that out from trigonometry then good job! Okay, so x = \(\sqrt{3} r\) What is r = ? \[r =\frac{x}{\sqrt{3}}\] \[C = 2 \pi ~(r)~\] \[C = 2 \pi ~(\frac{x}{\sqrt{3}})\] \[C = \frac{2}{\sqrt{3}} \pi x\] \[C(x) = \frac{2}{\sqrt{3}} \pi x\] Hence, you have successfully shown C as a function of x (which IS the side of the equilateral triangle). Understood? :)
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