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ln(ln(e^e)0
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Logarithm rules still work. \(\ln(\ln(e^{2})) = \ln(2\ln(e))\)
but the e is raised to itself. i do not understand that
'e' is just a number. Why is it different from any other number?
Sorry, \(\ln(\ln(e^{e})) = \ln(e\cdot\ln(e))\) Not sure how that 2 got in there.
@vitho What does the 0 at the end mean?
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The zero on the end is a typo. It should be a right parenthesis.
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