Question

help with math problem! asap!

Answer 1

1. Late one night a burglar somehow got into one of the vaults in Bank of America and started out with a big sack of money. No one really knows how much he stole. On his way out, he was stopped by one of the guards, who caught him "holding the bag" so to speak. Fortunately for him, the burglar was able to talk his way out of trouble by offering the guard half the money he had taken with a bonus of $2,000 thrown in. Just as he was walking away, praising his good luck at having gotten free, he was stopped by a second guard. He took the same bribe, half of all the money he had left, with $2,000 thrown in, to get by the second guard. Just as he was about to leave, you guessed it, he was stopped by yet a third guard who let him go only after receiving half of all the burglar had left, with $2,000 thrown in.

By the time the burglar left Bank of America he had mixed emotions. After all, he did leave with $9,000 more than he had when he arrived and he escaped a free man. But as he thought of all the money he had left behind with the guards, he wept.

Answer 2

so what is the question?

Answer 3

they're asking how much money he stole from the bank

Answer 4

work backwards
before he met the third guard he had 9000+9000+2000=20,000

Answer 5

@Asevilla5 how come you added $9000 twice? and added $2000 only once?

Answer 6

33,000

Answer 7

@Chris01 can you explain how you got it?

Answer 8

$9000*3=$27,000
$27,000+6000=$33,000

Answer 9

but he gave each guard twice the amount tho

Answer 10

Working backwards...
Assume the burglar had x dollars before he met the third guard.
He gave half the money to the third guard and an extra $2000.
So AFTER meeting the third guard, the burglar has: x - x/2 - 2000 = 9000
x/2 = 11,000
x = 22,000

Do a similar procedure with the second guard.
Assume the burglar had y dollars before meeting the second guard.
He gave half the money to the second guard and an extra $2000.
So AFTER meeting the second guard, the burglar has: y - y/2 - 2000 = 22,000
solve for y.

do the same with the first guard.

Answer 11

@Asevilla5 im sorry im still lost

Answer 12

I would cry too if I had only 9000 after stealing 100000

Answer 13

as @Asevilla5 suggested work backwards
let H = what he had h3 means after the 3rd guard, h2 after the 2nd etc
9000 = H3/2- 2000
h3 = (9000 + 2000) *2 = 22000
22000 = h2/2 + 2000
h2 = (22000 + 2000)*2 = 48000
48000= h1/2 + 2000
h1 = (48000 + 2000)*2= 100000

what he had originally is what he stole = 100000