Solve |2x + 1| = 10
walk me thru
2x+1=10 2x=9 x=9/2=4.5 the second answer is 2x+1=-10 2x=-11 x=-5.5
so x would be -11/2,9/2
Yep. And since you have | | signs, that is why @amirreza1870 set the problem |2x + 1| = 10 as 2x + 1 = 10 and 2x + 1 = -10
Because absolute value is saying it could be -10 or 10 units away from zero. Which is two solutions. Just in case you wanted to know why.
ok thank you
these are the problems i have the most difulculty find the answer Solve |4x - 8| < 12
So remember that when you have a problem with absolute values, get the absolute value by itself on one side of the equation first. Like with |x + 1| + 2 = 5 Then make it |x + 1| = 5 - 2 or |x+1| = 3 so that you can set up x + 1 = 3 x + 1 = -3 to solve it.
Ok so with inequalities, just replace the sign with an equals sign, solve for x, and then replace the equals back with the sign. Also, (making sure if you divide by anything negative to remember to flip the inequality when replacing it.)
|4x-8|=12
Since the absolute value is by itself, we set this up as 4x - 8 = 12 4x - 8 = -12 Then solve for x in both cases.
help realy stuck
4*4-8=12
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