Question

Commercially available concentrated HCL contains 38%HCL by mass.Then calculate the molarity of the solutionin 1.19 gm/l.what vol of concentrated HCL is required to make 1lof 0.1M HCL

Answer 1

"1.19 gm/l" makes no sense, so supposing 1.19 gm/mL"
Take a hypothetical sample of 1.000 L of the HCl solution:
(1000 mL) x (1.19 g/mL) x (0.38) / (36.4611 g HCl/mol) = 12.4 mol in 1 liter

(1 L) x (0.1 M) / (12.4 M) = 0.008 L = 8 mL