Question

Please help me 😔
10x^3 y^-5 z^-2
If x=3 y=2 z=5
Express your answer as a reduced fraction.

Answer 1

First, replace each variable with its value.
What do you get?

Answer 2

10 3^3 2^-5 5^-2

Answer 3

http://openstudy.com/study#/updates/5404974ae4b0f2ed1e1448e1

Answer 4

You're correct.

\(10 \times (3^3) \times (2^{-5}) \times (5^{-2}) \)

Now, turn each negative exponent into a fraction.

Answer 5

We raise 3^3 and we change the negative exponents into fractions.

\(10 \times (27) \times \dfrac{1}{2^5} \times \dfrac{1}{5^2} \)

Now raise 2^5 and 5^2, and set the entire product as one single fraction.

Answer 6

So i multiply 2^5 and 5^2

Answer 7

First, raise the numbers to the exponents.
Remember, 2^5 = 2 * 2 * 2 * 2 * 2, and 5^2 = 5 * 5

Answer 8

So 10 and 25

Answer 9

I dont get it

Answer 10

No.
Exponents mean repeated multiplication.
3^1 = 3
3^2 = 3 * 3 = 9
3^3 = 3 * 3 * 3 = 27
3^4 = 3 * 3 * 3 * 3 = 81

So 2^5 = 2 * 2 * 2 * 2 * 2 = 32
and 5^2 = 5 * 5 = 25

Answer 11

\(=10 \times (27) \times \dfrac{1}{2^5} \times \dfrac{1}{5^2}\)

\(=\dfrac{10 \times 27} {2^5 \times 5^2} \)


\(=\dfrac{10 \times 27} {32 \times 25} \)

\(=\dfrac{2 \times5 \times 27} {2 \times 16 \times 5 \times 5} \)

\(=\dfrac{\cancel{2} \times \cancel{5} \times 27} {\cancel{2} \times 16 \times \cancel{5} \times 5} \)

\(= \dfrac{27}{80} \)