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2^i how to i simplify
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2^i is a very weird number. Just like saying that you have 3½ friends.... if you know what I mean, you are multiplying 2 "i" number of times, even though, "i" doesn't really have a value. I can simplify i^2, but if it is 2^i, I would not be playing around with it.
\[i = \sqrt{-1}\] \[2^{i} = 2^{\sqrt{-1}}\] That's all I can come up with.
\[\Large 2^i=\left(e^{\ln2}\right)^i=e^{i\ln2}=\cos(\ln2)+i\sin(\ln2)\]
and that is to "simplify" ?
Well I would think a complex number in \(a+bi\) form is easier to work with, no?
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