Please help: x+1/x+2=x+3/x-1=1
solve for x
\[x + 1 \div x + 2 = x + 3 \div x - 1 = 1\]
@januaryjoy29 what is the first step you do when solving for a variable?
If you don't know, that's completely fine :)
sorry i dont know, clueless
Ok don't worry!
1st step you would do is isolate the variable
This basically means to get it alone so you can have something like: x = 1 or x = 7 Those are not the answers, just examples :)
im trying to understand
Don't worry I'm gonna try explain this the best I can because I remember when I had trouble with Algebra :P
ok thanks
Sorry I got disconnected from the site, it does that sometimes :D
The problem involves: Solving a rational equation that simplifies to quadratic: Binomial denominators and numerators
\[x + 1 \div x + 2 = x + 3 \div x - 1 = 1\] Add 1 to the negative 1 and the positive two You get \[x + 1 \div x + 3 = x + 3 \div x = 1\]
the answer is suppose to be two numbers like:0,6
\[x+1÷x+3=x+3÷x=1 \] Subtract 3 from the positive 3 on both sides You get \[x + 1 \div x = x \div x = 1\]
so your saying the answer is 1?
ok thanks s much
The answer is not 1, we are solving for x
Can you post you answer choices?
@januaryjoy29 Can you post your answer choices?
Ok so when we come to the point \[x \div x = x \div x = 1\] We see that this equation is true. So x does equal 1. The reason why I said x wasn't 1 earlier is because solving for equations early when you think you know the answer CAN be disastrous and I discourage it. Though when it is clear as this, you need not solve further unless your teacher tells you to do so.
its the Aleks system yo have to figure it out
Aleks system?
yes
Haha what is that?
online system..thank you for all your help
Join our real-time social learning platform and learn together with your friends!