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Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -6 and 162, respectively.
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nth term of a GS = a1r^(n-1) where r = common ration the r multiplies each term to get the next so 6th term / 2nd term = r^4
sorry its 2nd and 5th so we have 5th / 2nd = 162/ -6 = r^3
r^3 = -27 can you continue?
are we jus cubing the numbers?
yea
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so r^3= 64
s r = cube root of -27
so r= 3
now - its -27
so -3
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right now you can find the first term and plug that and r into the formula
2 x (-3)^n-1
right
it might be better to leave the x out nth term = 2(-3)^(n-1)
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