To test the accuracy of an industrial scale to 0.02 lb, an object which is known to be 107 lb is placed on the scale.
To test the accuracy of an industrial scale to 0.02 lb, an object which is known to be 107 lb is placed on the scale. a. Write an absolute value inequality that shows the measured weight of the object if the scale is NOT within accuracy standards. Options ; 1. |x − 107| > 0.02 2. |x − 107| < 0.02 3. |x + 107| ≤ 0.02 4. |x − 107| ≤ 0.02 5. |x + 107| > 0.02
Do you know what the pair of pipes mean that are either side of the expressions on the left hand side? Also do you know what x stands for?
x is what the value could be arent the || used for absolute value
Yes, the pipe symbols are used to indicate the absolute value of the expression inside. The variable x stands for the weight that is indicated by the scale under test. If the indicated weight was 106 lb, the expression |x - 107| would equal 1 lb. Also if the indicated weight was 108 lb, the expression |x - 107| would equal 1 lb. In each of these cases the indicated weight differs from the actual weight by 1 lb, showing that the scale does not comply with the accuracy specification of plus or minus 0.02 lb. Obviously the answer choices 3 and 5 cannot be correct, the reason being that the indicated and the actual weights must be subtracted, not added. Can you now find the correct choice?
1
Choice 1 is correct. Good work!
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