Question

Two vectors A and B are shown in the x-y plane. Vector A has a magnitude of 5 m and makes an angle of 55° with the positive x-axis vector B has a magnitude of 2 m and makes an angle of 33° with the negative x-axis. (See the figure above.) Vector C (not shown in the diagram) is the difference of A and B (C = A - B).

Answer 1

Hello @dp12345 !
Welcome to OpenStudy !

Answer 2

Angle between A vector and b vector will be 180-(55+33)=92°

Using the formula \(\sf A-B=\sqrt{A^2+B^2-2ABCos\theta}\) you can find the value of C.
Take A=5, B=2 and \(\sf \theta\)=92