Calculus: Evaluate lim as x->1 of (1- (1/x))/(1-(1/sqrt(x)))
\[\large \frac{1-\frac{1}{x}}{1-\frac{1}{\sqrt{x}}}\]?
Yes @satellite73
Is the answer is 2?
According to wolfram alpha, yes the answer is 2, but please help me how to approach this problem?
idk i didn't to it the first obvious thing to do since it is of the form \(\frac{0}{0}\) is to use l'hopital, but that is probably no allowed and it is not necessary the next thing would be to get rid of the compound fraction
or use wolfram lol
Nope l'hopital at this point is no good haha
can you think of anything to sandwich this with?
k then get rid of the compound fraction
no sandwich, it is all algebra
First,simplify the numerator and denominator.
okay.. I'll try getting rid of the compound fraction then
multiply top and bottom by \(x\)
then probably it would be a good idea to rationalize the denominator
Rationalise the denominator.
isnt the second step\[\frac{x-1}{x-\frac{x}{\sqrt(x)}}\] ?
good question! yes but \[\frac{x}{\sqrt{x}}=\sqrt{x}\]
oh wow.. I learn new things everyday haha, thanks for that
you are four steps away 1) rationalize the denomiator 2) factor the denominator 3) cancel (which was the whole point of this) 4) plug in 1
ah you knew \[\frac{x}{\sqrt{x}}=\sqrt{x}\] already either subtract the exponents, or else square \(\frac{x}{\sqrt{x}}\) and see that you get \(x\)
did you complete step one yet? rationalize the denominator?
I've actually successfully evaluated the limit. Thanks so much!!
And no it wasn't obvious at first that x/sqrt(x) is just sqrt(x)
yw hope it was clear gimmick is to cancel \(x-1\) to get rid of the 0 top and bottom
I had to evaluate it to see for myself haha. thanks!
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