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Mathematics 11 Online
OpenStudy (amtran_bus):

Can someone check my work??

OpenStudy (amtran_bus):

OpenStudy (amtran_bus):

I need help with that last resultant part if the rest is correct.

OpenStudy (phi):

they probably want numbers in the boxes (not the formula) if you do that, the resultant will be the sum of the numbers (for x) and the sum of the y's

OpenStudy (amtran_bus):

Ok. I was wondering about that. Thanks phi!

OpenStudy (amtran_bus):

How would you go about drawing the resultant? I am bad with that.

OpenStudy (phi):

first, get the x and y components. what are they ?

OpenStudy (amtran_bus):

It'll take me a min to add them up. My guess is that I add the x and y and just do what I did for the other boxes?

OpenStudy (amtran_bus):

___magnitude at ___ degrees?

OpenStudy (phi):

you add up *only the x's* to get the resultant x then add up only the y's to get the resultant y

OpenStudy (amtran_bus):

For the x I got -6.18614

OpenStudy (phi):

yes

OpenStudy (amtran_bus):

For Y I got 8.3572

OpenStudy (phi):

yes

OpenStudy (phi):

you can plot the point (-6.186, 8.357) then draw a vector from 0,0 to that point

OpenStudy (amtran_bus):

Can do! Thanks so much!

OpenStudy (phi):

they also want the length (magnitude) and angle pythagoras gives the length tan(angle) = y/x = 8.357/-6.186

OpenStudy (amtran_bus):

So basically I will plot the point, draw the vector from 0,0 at that angle?

OpenStudy (phi):

it's easiest (if you know (x,y) ) to plot the (x,y) point and draw a line from (0,0) to (x,y) in other words, from (0,0) to (-6.2, 8.4) (I rounded.... plotting is not that accurate)

OpenStudy (amtran_bus):

Ok.

OpenStudy (amtran_bus):

Sorry for being so slow with this. I get that part. The angle though, where does it come to play in that?

OpenStudy (phi):

Based on the picture, you can see the angle will be in the second quadrant.

OpenStudy (phi):

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