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\[\frac{ x (x+8)+20*(x+2)}{ (x+2)(x+8) }= 2\]
x(x+8)+20(x+2)=2(x+2)(x+8) now open the bracket and do further calculations
yeah -x^2+8x+8=0 or x^2-8x-8=0
solve the equation now
I don't get that exactly. I get \[x=4 \pm 2\sqrt{2}\]
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\[\frac{ -(-8) \pm \sqrt{64-4*8} }{ 2 }\]
\[\frac{ 8 \pm \sqrt{32} }{ 2 }\]
Making sense, @EcoBoost ?
Ok. Let me know if you got to here. :)
Oh wait!
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I didn't plug in my c as negative!
I used the second one.
I like for the coefficient of x^2 to be positive.
But either one works :)
And now I get \[4 \pm 2\sqrt{6}\]
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No worries :)
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