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Chemistry 16 Online
OpenStudy (anonymous):

let me know if there is anyone that can actually answer my question before i repost it again smh

OpenStudy (anonymous):

i said n-pentane and 1-butanol am i right? @esamalaa

OpenStudy (anonymous):

I'm sorry, I have no idea.... :(

OpenStudy (anonymous):

kay thanks anyway @MelissaHolmes

OpenStudy (hugsnotughs):

I am not sure. I have never learned of this kind of stuff, but in a couple of minutes I will have time to do some research on this. I'll try to help the best I can. :)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

thanks @hugsnotughs

OpenStudy (hugsnotughs):

Okay, so at the moment I don't have the time to see if you're answer is right, but I did find out how to find the London Disperson Force and this will definitely be useful for the "How was this proven" part and to check if you are correct. So basically, the larger the molecule, the greater the London dispersion forces. This is because larger molecules have a bigger electron cloud, thus creating a stronger temporary dipole when the electrons become asymmetrically distributed.

OpenStudy (hugsnotughs):

Long, skinny molecules have stronger London forces than short, fat ones. This is because of the increase in the amount of surface area- more spots to temporarily attract to neighboring molecules.

OpenStudy (hugsnotughs):

That's all I know, sorry. (>~<)

OpenStudy (anonymous):

thank you

OpenStudy (hugsnotughs):

You're very welcome and I am sorry I couldn't help you in all your question. Hope you get a good grade. :)

OpenStudy (abb0t):

Yes?

OpenStudy (anonymous):

are my answers for this correct

OpenStudy (abb0t):

Ask @nincompoop

OpenStudy (anonymous):

no idea on organic chemistry... sorry :-(

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