Question

how to solve (2y+3)^2=9

Answer 1

First, square root both sides and you get
2y+3=3
Now subtract 3 on both sides
2y=0
Now divide by 2
y=0 is your final answer

Answer 2

(2y+3)(2y+3) = 9
4y^2+6y+6y+9 = 9
4y^2+12y+9 = 9
4y^2+12 = 0

from there use quadratic formula or factoring

Answer 3

* 4y^2 + 12y = 0

Answer 4

\((2y+3)^2=9\)
Take square root on both sides:
\(2y + 3 = \pm 3\)
2y + 3 = 3
2y = 0
y = 0

2y + 3 = -3
2y = -6
y = -3

y = -3 and y = 0.

Answer 5

thank y'all (:

Answer 6

how to solve for \[6x^2+2x-1=0\]