The potential power output in Watts of a windmill can be approximated by P=12CρAv3where C is the capacity, ρ is the air density, A is the swept area, and v wind speed. Use the power potential to find the potential power output in Watts of a windmill of blades 25 meters long operating with 10% capacity if the wind is blowing 5 meters per second with air density 1.21 kgm2. Round your answer to the nearest integer, if needed. swept area= 1963.49
Correct
No the swept area is "A" which you plug into the equation
\[\large P=12\times0.1\times1.21\times1963.49\times5^{3}=you\ can\ calculate\]
i get 14848.89
I get a much higher result than that.
oh and its not 12 its 1/2
its p= 1/2* 0.1* 1.21* 1963.49*125
Yes, with your correction I get 14.849 kW (rounded to the nearest watt.
is it 14,849 or 14.849?
14.849 kW or 14,849 W.
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