Question

how to solve 4-(1/x)-(2/x^2)=0

Answer 1

This is a quadratic if you let u=1/x
try it.

Answer 2

Can yu solve 4-u-2u^2=0?
or -2u^2-u+4=0?

Answer 3

im not sure where "u" comes into play

Answer 4

You don't have to solve it that way, though you can if you want. You could also multiply the equation by the LCD.

Answer 5

To clear the fraction.

Answer 6

Either way.

Answer 7

@vanne29
I just let u=1/x and seen that u^2=1/x and made substitutions.

Answer 8

To get a quadratic.

Answer 9

oops u^2=1/x^2*

Answer 10

if i use the LCD method would i get 4x^2-1x-2=0?

Answer 11

yep

Answer 12

& then i use \[x=-b \pm\frac{ \sqrt{b ^{2}}-4ac }{ 2a }\] and plug in those number right?

Answer 13

I think you mean
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 14

And if is that then yes

Answer 15

the answer would be x=\[\pm \frac{ \sqrt{33} }{ 8 }\]

Answer 16

\[1\pm \frac{ \sqrt{33} }{ 8}\]

Answer 17

you mean \[x=\frac{1\pm \sqrt{33}}{8}\]?