WHAT ARE THE CONCENTRATIONS OF H30+ AND OH- in tomatoes that have pH oh 4.14
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OpenStudy (toxicsugar22):
DO H30+ FIRST
THEN OH-
OpenStudy (toxicsugar22):
so walk me throught the steps
OpenStudy (anonymous):
PH = 4.14 it is a acid solution
OpenStudy (anonymous):
Ph = 4.14< 7
OpenStudy (toxicsugar22):
so what is H30+
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OpenStudy (toxicsugar22):
ANSWER
OpenStudy (toxicsugar22):
is is -.617
OpenStudy (toxicsugar22):
is it -log(4.14) to get H30+
I GOT -.617
OpenStudy (anonymous):
nnnnnnnoooooo
PH = -log H3O+ and POH = -Log OH-
H3O+ = e -PH and OH- = e-POH
we have ph = 4.14 it is an acid selution so :
H3O+ = e-4.14
POH = 14 - PH = 14-4.14=9.86 so OH- = e-9.86
since we have an acide solution so [H3O+] must be >>>>>>> [OH-]
so we get that because e-4.14 >>> e-9.86
us i know ....... thanks
OpenStudy (jfraser):
to find pH from concentration, you take the -log(H3O+)
to find concentration from pH, you have to do the inverse function, use \(10^{-pH}\)
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OpenStudy (toxicsugar22):
so it is [H30+]=1*10^4.14
and [0H-]=1*10^9.86
OpenStudy (toxicsugar22):
IT IS RIGHT
OpenStudy (joannablackwelder):
Close. It is 10^-4.14 for [H3O=]
OpenStudy (toxicsugar22):
so fore [H30+]=1*10^-4.14
and what about [OH-]=
OpenStudy (joannablackwelder):
You will need to calculate the value for [H3O+] first. Can you put that in your calculator?
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