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Mathematics 13 Online
OpenStudy (anonymous):

tan^2x+1/cos^2x

OpenStudy (anonymous):

So far i go sec^2x/cos^2x

OpenStudy (anonymous):

good, and \(sec = \dfrac{1}{cos}\) or \(cos = \dfrac{1}{sec}\) , just replace to get the simplest form.

OpenStudy (anonymous):

so if its squared what would it look like

OpenStudy (anonymous):

the same.!!

OpenStudy (anonymous):

1/cos^2/1/sec^2

OpenStudy (anonymous):

see!! |dw:1409747240329:dw|

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