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Mathematics 22 Online
OpenStudy (anonymous):

Decide whether the given x value is a zero of the function. f(x) = x3 + 3x2 – 5x + 8; x = 4

OpenStudy (anonymous):

a. No, because there is more than one zero . b. No, because substituting the value does not balance the equation. c. Yes, because substituting the value does balance the equation. d. none of the above

OpenStudy (kirbykirby):

Well a zero is a value such that when you plug it in, you output 0. That is you should check if f(4) = 0

OpenStudy (anonymous):

I got a hundred. Would the answer b A?

OpenStudy (anonymous):

@kirbykirby

OpenStudy (kirbykirby):

well it's true that 4 is not a zero.. but you should check if there is more than one zero fr this problem (the reasoning for the "No" might not be correct... ) b) doesn't make sense what the reasoning is.. because you aren't verifying if anything is being balanced. You are plugging in a value for x and THEN checking what that output value is, but it's not a "verification" because you don't know the initial output you're checking

OpenStudy (kirbykirby):

To check how many zeros your function has, you can check what the zeros are by solving for x: \(0 = x^3 + 3x^2 – 5x + 8\)

OpenStudy (kirbykirby):

Actually this is not such a nice function.. you could actually just graph it and see how many zeros you have: http://www.wolframalpha.com/input/?i=x3+%2B+3x2+%E2%80%93+5x+%2B+8

OpenStudy (anonymous):

How do I find out how many zeros I have

OpenStudy (kirbykirby):

well check how many times the graph crosses the x-axis (in the link I provided)

OpenStudy (anonymous):

2 times?

OpenStudy (kirbykirby):

it only crosses once (a bit to the left of -4 )

OpenStudy (kirbykirby):

wait actually... have you seen complex numbers?

OpenStudy (anonymous):

yes

OpenStudy (kirbykirby):

Ah ok then.. actually it will have more than one zero if you consider complex roots (This is from the Fundamental Theorem of Algebra) , then

OpenStudy (kirbykirby):

then A would be right

OpenStudy (anonymous):

Okay. Thank you so much for your help!

OpenStudy (kirbykirby):

=]

OpenStudy (anonymous):

can you help me with some more?

OpenStudy (kirbykirby):

ok

OpenStudy (anonymous):

The Fundamental Theorem of Algebra helps to: a. solve irrational equations b. solve quadratic equations c. solve linear equations d. solve rational equations

OpenStudy (kirbykirby):

can you select more than 1?

OpenStudy (anonymous):

no I can't

OpenStudy (kirbykirby):

well it's not a or d for sure.

OpenStudy (kirbykirby):

I guess its more useful for a quadratic equation since linear equations are simple

OpenStudy (anonymous):

okay thank you

OpenStudy (anonymous):

what about this one A root can be described as: a. a solution to the base of leading coefficient b. a solution to the equation c. an answer to the inverse equation d. none of the above

OpenStudy (kirbykirby):

I feel like it's d.. the statement"a solution to the equation" is very vague. It could be a solution to the equation if you know the y-value .

OpenStudy (kirbykirby):

Because a function is not technically an equation. It's more like a relation

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