CAN SOMEONE TEACH ME HOW TO FACTOR
List a few examples that you are trying to factor.
5x^2-3x+3
First Lesson: Become wonderful at Factorization of Integers. ax^2 + bx + c = 0 Find ALL the factorizations of 'a'. Find ALL the factorizations of 'c'. 3x^2 + bx + 2 = 0 Simple: All the factorizations of 3 are 1*3 and 3*1 All the factorizations of 2 are 1*2 and 2*1 12x^2 + bx + 15 = 0 Not so Simple: All the factorizations of 12 are 1*12, 2*6, 3*4, 4*3, 6*2, 12*1 All the factorizations of 15 are 1*15, 3*5, 5*3, and 15*1 Okay, there is Lesson #1. Try some. 7x^2 + bx + 9 = 0 8x^2 + bx + 24 = 0 Challenge Problem: (3/2)x^2 + bx + 5 = 0
can you show me more steps
You haven't done your homework assignment.
idu how
It's up there at the bottom of my first post. Demonstrate those factorings.
oh ok
In addition there are several websites and YouTube videos that show step-by-step procedure to factor quadratic expressions. Here is one such website: http://www.purplemath.com/modules/factquad.htm
Yup. I like PurpleMath. There are plenty of resources.
7x^2 + bx + 9 = 0 All the factorizations of 7 are 1*7 All the factorizations of 9 are 1*9 , 3*3, 8x^2 + bx + 24 = 0 All the factorizations of 8 are 2*4 and 8*1 All the factorizations of 24 are 1*24 , 2*12, 6*4 and 3*8 Challenge Problem: (3/2)x^2 + bx + 5 = 0 All the factorizations of 3/2 are 3/2*1 All the factorizations of 5 are 1*5
@tk
@tkhunny
Okay, a couple of things. For 'a', all you really need is the one direction, 1*7 will serve about as well as 7*1. For 'c', this is not the case. You need BOTH. 1*7 and 7*1. Don't get caught up in thinking there is only one pair when order matters. As for the challenge problem, (3/2)x^2 + bx + 5 = 0 You should have noted that factorization isn't particularly useful unless you have INTEGERS. You should first have multiplied the entire equation by 2. 3x^2 + 2bx + 10 = 0 Now we see, a) 1*3 or 3*1 c) 1*10, 2*5, 5*2, 10*1 Are we making any sense?
yes
Okay, now we get to think about the sign of c. If it is positive, we are done with possibilities. If it is negative, we just doubled our potential work. 3x^2 + bx + 2 = 0 Simple: All the factorizations of 2 are 1*2 and 2*1 3x^2 + bx - 2 = 0 Simple: All the factorizations of 2 are 1*2 and 2*1, but to get -2, that is now These (-1)*2 and (-2)*1 and 1*(-2) and 2*(-1) Okay, now we have ALL the possibilities written down. There are LOTS of Rational Numbers. It shoudl not be surprising that there can be quite a list. Still making sense? 12x^2 + bx + 15 = 0 Not so Simple: All the factorizations of 12 are 1*12, 2*6, 3*4, 4*3, 6*2, 12*1 All the factorizations of 15 are 1*15, 3*5, 5*3, and 15*1
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