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Mathematics 20 Online
OpenStudy (anonymous):

CAN SOMEONE TEACH ME HOW TO FACTOR

OpenStudy (aum):

List a few examples that you are trying to factor.

OpenStudy (anonymous):

5x^2-3x+3

OpenStudy (tkhunny):

First Lesson: Become wonderful at Factorization of Integers. ax^2 + bx + c = 0 Find ALL the factorizations of 'a'. Find ALL the factorizations of 'c'. 3x^2 + bx + 2 = 0 Simple: All the factorizations of 3 are 1*3 and 3*1 All the factorizations of 2 are 1*2 and 2*1 12x^2 + bx + 15 = 0 Not so Simple: All the factorizations of 12 are 1*12, 2*6, 3*4, 4*3, 6*2, 12*1 All the factorizations of 15 are 1*15, 3*5, 5*3, and 15*1 Okay, there is Lesson #1. Try some. 7x^2 + bx + 9 = 0 8x^2 + bx + 24 = 0 Challenge Problem: (3/2)x^2 + bx + 5 = 0

OpenStudy (anonymous):

can you show me more steps

OpenStudy (tkhunny):

You haven't done your homework assignment.

OpenStudy (anonymous):

idu how

OpenStudy (tkhunny):

It's up there at the bottom of my first post. Demonstrate those factorings.

OpenStudy (anonymous):

oh ok

OpenStudy (aum):

In addition there are several websites and YouTube videos that show step-by-step procedure to factor quadratic expressions. Here is one such website: http://www.purplemath.com/modules/factquad.htm

OpenStudy (tkhunny):

Yup. I like PurpleMath. There are plenty of resources.

OpenStudy (anonymous):

7x^2 + bx + 9 = 0 All the factorizations of 7 are 1*7 All the factorizations of 9 are 1*9 , 3*3, 8x^2 + bx + 24 = 0 All the factorizations of 8 are 2*4 and 8*1 All the factorizations of 24 are 1*24 , 2*12, 6*4 and 3*8 Challenge Problem: (3/2)x^2 + bx + 5 = 0 All the factorizations of 3/2 are 3/2*1 All the factorizations of 5 are 1*5

OpenStudy (anonymous):

@tk

OpenStudy (anonymous):

@tkhunny

OpenStudy (tkhunny):

Okay, a couple of things. For 'a', all you really need is the one direction, 1*7 will serve about as well as 7*1. For 'c', this is not the case. You need BOTH. 1*7 and 7*1. Don't get caught up in thinking there is only one pair when order matters. As for the challenge problem, (3/2)x^2 + bx + 5 = 0 You should have noted that factorization isn't particularly useful unless you have INTEGERS. You should first have multiplied the entire equation by 2. 3x^2 + 2bx + 10 = 0 Now we see, a) 1*3 or 3*1 c) 1*10, 2*5, 5*2, 10*1 Are we making any sense?

OpenStudy (anonymous):

yes

OpenStudy (tkhunny):

Okay, now we get to think about the sign of c. If it is positive, we are done with possibilities. If it is negative, we just doubled our potential work. 3x^2 + bx + 2 = 0 Simple: All the factorizations of 2 are 1*2 and 2*1 3x^2 + bx - 2 = 0 Simple: All the factorizations of 2 are 1*2 and 2*1, but to get -2, that is now These (-1)*2 and (-2)*1 and 1*(-2) and 2*(-1) Okay, now we have ALL the possibilities written down. There are LOTS of Rational Numbers. It shoudl not be surprising that there can be quite a list. Still making sense? 12x^2 + bx + 15 = 0 Not so Simple: All the factorizations of 12 are 1*12, 2*6, 3*4, 4*3, 6*2, 12*1 All the factorizations of 15 are 1*15, 3*5, 5*3, and 15*1

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