Question

Can anybody help me with a couple of math questions?

Answer 1

Only if you ask them

Answer 2

The biggest one I need help with is P1 times V1 over T1= P2 times V2 over T2
Solve for T2

Answer 3

\[\large \frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\]??

Answer 4

Is it as easy as subtracting P2V2 from both sides?

Answer 5

no

Answer 6

but it is easy
you want \(T_2\) right?

Answer 7

Yes. I need to solve for T2

Answer 8

flip both sides to get it in the numerator first

Answer 9

clear?

Answer 10

no is a fine answer, i can show you
just asking

Answer 11

Is T1 over P1V1 times P2V2=T2 correct?

Answer 12

yes

Answer 13

Thank you! Do you mind helping me with a couple more?

Answer 14

you can write it as
\[\frac{P_1V_1P_2V_2}{T_1}\] if you like

Answer 15

k

Answer 16

I need to know how to write a base with an exponent as a fraction
Like 4 to the -2 power

Answer 17

\[\large 4^{-2}\]?

Answer 18

Yes

Answer 19

\[\large b^{-n}=\frac{1}{b^n}\]

Answer 20

so
\[\large 4^{-2}=\frac{1}{4^2}=\frac{1}{16}\]

Answer 21

Okay. Just one more. This one is really simple but math isn't my strong suit. It stresses me out.
Does \[4^{1}\times 4^{-3}\] equal \[4^{-2}\]

Answer 22

yes because \(1-3=-2\)

Answer 23

i will be happy to help with more if you need
no problem

Answer 24

Okay so 4 to the first power divided by 4 to the third power is equal to 4 to the first power times 4 to the negative third power?

Answer 25

\[\frac{4}{4^3}=\frac{1}{4^2}\] by cancelling
you can write
\[\frac{1}{4^2}\] as \(4^{-2}\)

Answer 26

or you can write
\[\frac{4}{4^3}=4\times 4^{-3}=4^{1-3}=4^{-2}\] it is all the same really

Answer 27

Okay. Thank you so much!!!

Answer 28

yw