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Physics 9 Online
OpenStudy (anonymous):

Could someone please check my work on this conductivity question?

OpenStudy (anonymous):

OpenStudy (anonymous):

ok you have corrected the units... i re-calculate it and got the same...

OpenStudy (anonymous):

Check you conversion from deg C to Deg K.

OpenStudy (radar):

I believe the conversion is O.K. 100 degrees F is equivalent to 310.928 degrees Kelvin.

OpenStudy (anonymous):

Not quite. the temperature difference in deg C = temp diff in deg K. \[K ^{0} = 273.16+ C ^{0} \rightarrow \Delta K ^{0} =\Delta C ^{0} \]

OpenStudy (anonymous):

Ahh! @gleem, you're right! Thank you! I didn't think about that. I will correct my work, and post the results shortly.

OpenStudy (anonymous):

Here is my revised work. These numbers seem much more reasonable.

OpenStudy (radar):

Obviously, I didn't either. Sorry for the wrong data.

OpenStudy (anonymous):

ok got it...

OpenStudy (anonymous):

Not a problem @radar / @Orion1213 , that totally slipped past me. I appreciate your help and taking the time to look into my problem. Thank you!

OpenStudy (anonymous):

thanks @LolGoCryAboutIt ... i learned too from your problem... \(\ddot\smile\)

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