Question

The molar mass of NH3 is 17.03 g/mol. How many moles of O2 are required to react completely with 2.67 x 10 to the -4 g of NH3?

Answer 1

1. First figure out what the product is when NH3 reacts with O2 *You can just look it up, type it in a search engine or guess I will let you know if you are right

O2 + NH3 -> ?

2. Balance the equation
( https://www.youtube.com/results?search_query=balance+equations watch one of these videos)

4. Convert 2.67*10^-4g to moles of NH3 using:
moles = grams/Molecular mass

You will need molecular mass of NH3 so, 17.03 g/mol

Molecular mass = molar mass
(video on it here https://www.youtube.com/watch?v=Ik4zE8lXWs8)

3. Divide by the number next to NH3 and multiply by the number next to O2 in the reaction equation that you balanced

4. Now you will have moles of O2 needed to completely react 2.67*10^-4g of NH3, all you need to do is convert to moles (how to convert to molar mass https://www.youtube.com/watch?v=F9NkYSKJifs)

So use the formula

moles = grams/Molecular mass

and solve for grams, you will need molecular mass of O2

Answer 2

4NH3+5O2 -> 4NO+ 6H2O