A chain store manager has been told by the main office that daily profit, P, is related to the number of clerks working that day, x, according to the equation P = -25x2 + 450x. What number of clerks will maximize the profit?
P(x) = -25x^2 + 450x differentiate - P'(x) = -50x + 450
dP/dx = -50x + 300 To find the max (or min), is where the gradient (dp/dx) is zero, so ask that... 0 = -50x + 300 hence x = 6. Prove it is a max too, by differentiating again...d2P/dx2 = -50. This is -ve therefore MAX So max number of clerks = 6. This maximises the profit, P to be \(-25*(6)^2+300*6\) max profit = 900 http://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.2375.html
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What number of clerks will maximize the profit?
6 is not right
9
Another source says 9.
Lol.
thank you so much , 9 is correct
:)
http://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.635228.html
do you know how to get 9?
yesss i solved it out . i had to show work
great.
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