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Mathematics 15 Online
OpenStudy (sedatefrog712):

Medal An expression is shown below: 3x3y + 12xy - 3x2y - 12y Part A: Rewrite the expression so that the GCF is factored completely. (3 points) Part B: Rewrite the expression completely factored. Show the steps of your work. (4 points) Part C: If the two middle terms were switched so that the expression became 3x3y - 3x2y + 12xy - 12y, would the factored expression no longer be equivalent to your answer in part B? Explain your reasoning. (3 points)

OpenStudy (sedatefrog712):

@triciaal

OpenStudy (midhun.madhu1987):

Take the factor that is common to all the 4 terms... what u get?

OpenStudy (sedatefrog712):

x^3 + 4x - x^2 - 4 I believe

OpenStudy (triciaal):

part C no same result commutative property same as 3 + 4 = 4 + 3

OpenStudy (sedatefrog712):

ok but in part B do I just show them how I got pat A

OpenStudy (triciaal):

@midhun.madhu1987 is this what you got 3y(x-1)(x^2 + 4)

OpenStudy (midhun.madhu1987):

which part? @triciaal

OpenStudy (triciaal):

@SedateFrog712 when you divide to factor an expression you leave the factor outside parenthesis. so what did you divide by

OpenStudy (triciaal):

@midhun.madhu1987 b

OpenStudy (sedatefrog712):

I divide by 3 because it was the gcf

OpenStudy (triciaal):

is that all you divided by

OpenStudy (sedatefrog712):

yes for part a

OpenStudy (midhun.madhu1987):

yes.. @triciaal

OpenStudy (triciaal):

the factors when multiplied must be equal to what is being factored

OpenStudy (triciaal):

example what are the factors of 12 use 3 and 4 then 3*4 = 12 what if you had 6 + 15 common is 3 so 3 *2 + 3 *5 when factored would be 3(2 + 5) still 15 otherwise it becomes a division problem

OpenStudy (triciaal):

after reading the example now ,what is the GCF for the expression

OpenStudy (sedatefrog712):

3y

OpenStudy (triciaal):

yes

OpenStudy (sedatefrog712):

ok

OpenStudy (sedatefrog712):

so part a I would write down x^3 + 4x - x^2 - 4 and then in B I would explain how I got that correct

OpenStudy (triciaal):

no Part A: Rewrite the expression remember in the example how I rewrote 15 so it was still 15? do the same

OpenStudy (sedatefrog712):

so I would write down 3x3y + 12xy - 3x2y - 12y

OpenStudy (triciaal):

Part B: Rewrite the expression COMPLETELY factored.

OpenStudy (sedatefrog712):

3x3y + 12xy - 3x2y - 12y 3y(3x3y + 12xy - 3x2y - 12y) x^3 + 4x - x^2 - 4

OpenStudy (triciaal):

PART A look at the post again when factored would be 3(2 + 5) still 15 3x3y + 12xy - 3x2y - 12y would be 3y (x^3 + 4x - x^2 - 4)

OpenStudy (sedatefrog712):

oh ok I see im sorry for that I got a little confused for a while there

OpenStudy (triciaal):

I think you just need to understand the terminology rewrite express same thing solve find a value etc

OpenStudy (sedatefrog712):

ok

OpenStudy (triciaal):

now do part B factor COMPLETELY this means the part in ( ) can be factored what are the factors then rewrite the original expression

OpenStudy (sedatefrog712):

I would factor out an x for each so it would look like this (x^2+4) (x-4)

OpenStudy (triciaal):

part C is worth 3 points so you want want to prove you have the same results by reworking the problem with the middle terms switched and so the associate property

OpenStudy (triciaal):

when you multiply what you have do you get your original?

OpenStudy (triciaal):

repost the factors when multiplied must be equal to what is being factored

OpenStudy (sedatefrog712):

It would not be equivalent

OpenStudy (triciaal):

so try again

OpenStudy (sedatefrog712):

the reason it wouldn't tho is because if you used the GCF 3y it would look like this x^3-x^2+4x-4

OpenStudy (triciaal):

slow down and read the post to follow what is required.

OpenStudy (triciaal):

you factored out 3y and the other factor is ( ) now for part b factor ( ) correctly and when you are finish rewrite the expression to show all the factors 3y and what you get when you factor what is in ( )

OpenStudy (triciaal):

do you understand now?

OpenStudy (sedatefrog712):

kind of I think I got this one down now thank you so much if I have any more problems later would you mind helping me

OpenStudy (triciaal):

show what you got when you factored ( )

OpenStudy (triciaal):

no I don't mind helping you at all. That's why I take the time with you.

OpenStudy (triciaal):

The answer for b is above I just wanted to make sure you understand and can do it on your own

OpenStudy (triciaal):

have a good day

OpenStudy (sedatefrog712):

you to your the best

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