why is 18^1/5 called the 5th root of 18?
by definition
\(\Large \bf a^{\frac{{\color{blue} n}}{{\color{red} m}}} = \sqrt[{\color{red} m}]{a^{\color{blue} n}}\qquad thus\quad 18^{\frac{{\color{blue}{ 1}}}{{\color{red}{ 5}}}}\implies ?\)
@satellite73 i dont understand what you mean by that..
there is no such thing as multiplying a number by itself one fifth time we define \[\huge b^{\frac{1}{n}}\] to be \[\huge \sqrt[n]{b}\] in order to make the laws of exponents hold for fractional exponents as well as whole number exponents
one law of exponents is \[\large (b^n)^m=b^{m\times n}\] that means if \(b^{\frac{1}{n}}\) is to make sense then since \[\large (b^{\frac{1}{n}})^n=b^1=b\] making \[\large b^{\frac{1}{n}}=\sqrt[n]{b}\]
oh got it thanks for the help @satellite73
yw
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