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Mathematics 12 Online
OpenStudy (anonymous):

Help with findings area of irregular shape. WILL FAN AND MEDAL IMMEDIATELY.

OpenStudy (anonymous):

OpenStudy (anonymous):

You can break the shape apart into a rectangle and a triangle. All you have to do is find the area of both and add them together :)

OpenStudy (anonymous):

@TheWaffleMan149 Thanks - but what would the triangle side lengths be (that's my issue)... It's 2, 5, and what?

OpenStudy (anonymous):

You have to use the pythagorean theorem to find it

OpenStudy (anonymous):

a^2+b^2=c^2

OpenStudy (anonymous):

@TheWaffleMan149 I am getting 165 in^2 is that right?

OpenStudy (anonymous):

For the entire shape, that is.

OpenStudy (anonymous):

Ummm one sec

OpenStudy (anonymous):

Thank you.

OpenStudy (anonymous):

You don't even need the third side of the triangle btw. You just need the base and height

OpenStudy (anonymous):

I realized that afterwards. Please let me know if you get the same answer!

OpenStudy (anonymous):

Ok. Thats not what i got. I got 4in^2 for the triangle, and 150in^2 for the rectangle. Therefore the whole shape is 154 in^2

OpenStudy (anonymous):

Isn't the rectable 16x10 = 160, then the triangle is 1/2(2)x5 = 5 so then 160+5?

OpenStudy (anonymous):

rectangle*

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