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OpenStudy (anonymous):
Help with findings area of irregular shape. WILL FAN AND MEDAL IMMEDIATELY.
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OpenStudy (anonymous):
OpenStudy (anonymous):
You can break the shape apart into a rectangle and a triangle. All you have to do is find the area of both and add them together :)
OpenStudy (anonymous):
@TheWaffleMan149 Thanks - but what would the triangle side lengths be (that's my issue)... It's 2, 5, and what?
OpenStudy (anonymous):
You have to use the pythagorean theorem to find it
OpenStudy (anonymous):
a^2+b^2=c^2
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OpenStudy (anonymous):
@TheWaffleMan149 I am getting 165 in^2 is that right?
OpenStudy (anonymous):
For the entire shape, that is.
OpenStudy (anonymous):
Ummm one sec
OpenStudy (anonymous):
Thank you.
OpenStudy (anonymous):
You don't even need the third side of the triangle btw. You just need the base and height
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OpenStudy (anonymous):
I realized that afterwards. Please let me know if you get the same answer!
OpenStudy (anonymous):
Ok. Thats not what i got. I got 4in^2 for the triangle, and 150in^2 for the rectangle. Therefore the whole shape is 154 in^2
OpenStudy (anonymous):
Isn't the rectable 16x10 = 160, then the triangle is 1/2(2)x5 = 5 so then 160+5?
OpenStudy (anonymous):
rectangle*
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