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Mathematics 23 Online
OpenStudy (anonymous):

My question is in regards to number 3 on the below picture. The book wants me to find the points of continuity and the points of discontinuity of the function and to identify each type of discontinuity. My question is how am I supposed to do #3 with limits?

OpenStudy (anonymous):

Wait the pic was messed up

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

OpenStudy (anonymous):

This one is better

OpenStudy (anonymous):

What grade are you in?

OpenStudy (anonymous):

11th. AP Calc BC

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

Does the pic work?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

Ok. Now how to do it...

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

Wait one sec :T

OpenStudy (anonymous):

Ok, thanks!!!

OpenStudy (anonymous):

Np lol

OpenStudy (anonymous):

I gtg for like an hour.

OpenStudy (anonymous):

okm

OpenStudy (anonymous):

Ok, I'm back

OpenStudy (anonymous):

What do you already know about limits?

OpenStudy (anonymous):

?

OpenStudy (anonymous):

A lot?

OpenStudy (anonymous):

I don't know how to prove that this function is continuous. Thats the issue.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

I can't open that file

OpenStudy (anonymous):

Ok well it says

OpenStudy (dangerousjesse):

Most people don't download files from students :/

OpenStudy (anonymous):

|dw:1409877512647:dw|

OpenStudy (anonymous):

y=(1)/(x^2+1)

jimthompson5910 (jim_thompson5910):

can the denominator ever be equal to zero?

jimthompson5910 (jim_thompson5910):

ie, are there any solutions to x^2 + 1 = 0 ?

OpenStudy (anonymous):

Well excluding imaginary numbers, no

jimthompson5910 (jim_thompson5910):

so there are no real numbered values that you can plug into x to make x^2 + 1 = 0 true that means there is no possible way to divide by zero

OpenStudy (anonymous):

Yes

jimthompson5910 (jim_thompson5910):

visually this makes a graph with no discontinuities

OpenStudy (anonymous):

I know this, but I need to use limits

jimthompson5910 (jim_thompson5910):

there are no excluded values from the domain

OpenStudy (anonymous):

So there isn't a way to really prove this?

jimthompson5910 (jim_thompson5910):

that's the only way I can think of

OpenStudy (anonymous):

Ok, thanks for the help!

jimthompson5910 (jim_thompson5910):

sure thing

OpenStudy (anonymous):

Srry I couldn't help you WaffleMan You're really smart Jim

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